コンプリート！ 2^x 3^y=17 2^x 2-3^y 1=5 by elimination method 176296
Click here to see ALL problems on Equations Question Solve the system by elimination 2x2y3z=0 2xyz=3 2x3y3z=5 Answer by Alan3354 () ( Show Source ) You can put this solution on YOUR website! Transcript Example 17 Solve the pair of equations 2/𝑥 3/𝑦=13 5/𝑥−4/𝑦=−2 2/𝑥 3/𝑦=13 5/𝑥−4/𝑦=−2 So, our equations become 2u 3v = 13 5u – 4v = –2 Hence, our equations are 2u 3v = 13 (3) 5u – 4v = – 2 (4) From (3) 2u 3v = 13 2u = 13 – 3V u = (13 − 3𝑣)/2 Putting value of u (4) 5u – 4v = 2 5((13 − 3𝑣)/2)−4𝑣=−2 Multiplying If the linear equation in two variables 2x –y = 2, 3y –4x = 2and px–3y = 2are concurrent, then find the value of p If ܽa b = 35 and a − b = How To Solve 1 X 1 Y 7 2 X 3 Y 17 Where X And Y Is Not Equal To 0 By Cross Multiplication Method Quora 2^x 3^y=17 2^x 2-3^y 1=5 by elimination method